The power dissipated by the motor is given by: [tex]P=VI[/tex] where V is the voltage of the battery and I is the current flowing in the circuit.
In our problem, the voltage is V=12 V and the current is I=246 A, so we can calculate the power dissipated by the motor using the previous equation: [tex]P=(12 V)(246 A)=2952 W[/tex]