The work of a student to solve a set of equations is shown:
Equation A: y = 15 β 2z
Equation B: 2y = 3 β 4z
Step 1: β2(y) = β2(15 β 2z) [Equation A is multiplied by β2.]
2y = 3 β 4z [Equation B]
Step 2: β2y = 15 β 2z [Equation A in Step 1 is simplified.]
2y = 3 β 4z [Equation B]
Step 3: 0 = 18 β 6z [Equations in Step 2 are added.]
Step 4: 6z = 18
Step 5: z = 3
In which step did the student first make an error?
Step1
Step 2
Step 3
Step 4