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01-08-2019
Mathematics

contestada

If (x+5)^2=35, what is the appropriate positive value of x?

Respuesta :

marcthemathtutor marcthemathtutor

01-08-2019

Answer:

x = 0.916

Step-by-step explanation:

(x+5)² =35

(x+5) = ± √35

(x+5) = ± 5.916

Hence

x +5 = + 5.916 -----> x = 5.916 - 5= 0.916 (Answer)

or

x+5 = -5.916 -----> x = -5 -5.916 = -10.916 (ignore because question asked for positive value.

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