A student increases the temperature of a 200 cm3 balloon from 33degrees C to 47 degrease C. What will the new volume of the ballon be?

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01-06-2018
Chemistry

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A student increases the temperature of a 200 cm3 balloon from 33degrees C to 47 degrease C. What will the new volume of the ballon be?

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andriansp andriansp · Answer 1 · 2018-06-10T20:34:45+02:00

andriansp andriansp

10-06-2018

The answer is 209.15cm3

The volume is directly related to the temperature of a gas. You can solve this question using Charles' law, but remember to convert the temperature from Celcius to Kelvin.

V1/T1= V2/T2
200 cm3/ (33+273K)= V2/(47+273K)
V2= 200cm3 * 320/306= 209.15cm3

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